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A bead of mass M can slide on a thin vertical rod,with sliding friction coefficient between them=z. The rod is translated horizontally with a constant acceleration (a). For what value of (a) will an earth observer see equal horizotal and vertical components of acceleration of the bead?

sanki kurli
18 Points
10 years ago

the bead is sliding  vertically down with friction opposing its direction...

so net force on the bead vertically= M*g - z*N         ....N=normal reaction force=M*a

& net horizontal foce = M*a

the normal foce would be..N=M*a    (as N is in horizontal direction)

according tge cquestion.. the horizontal acce. =vertical acce.

=>(M*g - z*N ) /M = (M*a)/M

=>g - z*a = a

=>a =g/(1+z)