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Vijay Luxmi
applying cons. of momentum at 1st jump then,sign conven is taking right as positive.
mu=-(M+m)v
so v=-mu/(M+m)
now the velocity of 2nd jump is u wrt this velocity so,its velo. wrt ground is
v'=-Mu/(m+M)
applying cons. of momentum on 2nd jump we get,
-mu=Mv"-mMu/(M+m)
from this we get v" as your ans
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