HC Verma , Exercise question no. 28?

HC Verma , Exercise question no. 28?


2 Answers

Vijay Luxmi Askiitiansexpert
357 Points
11 years ago

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Vijay Luxmi

priyank sharma
37 Points
11 years ago

applying cons. of momentum at 1st jump then,sign conven is taking right as positive.


so v=-mu/(M+m)

now the velocity of 2nd jump is u wrt this velocity so,its velo. wrt ground is


applying cons. of momentum on 2nd jump we get,


from this we get v" as your ans

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