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a parrticle A is projected vewrtically upwards . another particle B of same mass is prijected at an angle 45 .both reach at same height . the ratio of intial kinetic energy of A to B ?
Hi Srishty,
Let Initial speeds of A be Va and of B be Vb.
let height be h.
Thus 2gh = (Va)2 and (Vb(sin45))2 = 2gh
Thus, (Va)2 = (Vb)2*(1/2)
Thus, (Va)2/(Vb)2 = 1/2
The ratio of Initial Kinetic energies of A and B is 1/2 because they have same Mass.
Please feel free to ask as many questions you have.
Puneet
For a 1 D motion,
H max = u^2/2g
In an oblique projection, H max = v^2 sin^2 (angle) / 2g
Here heights are same.
So :u^2 = v^2 sin^2(45)
u^2 / v^2 = 1
So, ratio of internal KE is 1:1 as masses are same........
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