Grade 12Mechanics

if a particle is projected from hight H with velocity v & angle ω, what is its maximum range?

shashank jyoti yadav

15 Years agoGrade 12

4 Answers

SAGAR SINGH - IIT DELHI

15 Years ago

Theta is same as w.

$x(t) = \frac{}{} v\cos \left(\theta\right) t$

In the vertical direction

$y(t) = \frac{} {} v\sin \left(\theta\right) t - \frac{1} {2} g t^2$

We are interested in the time when the projectile returns to the same height it originated at, thus

$0 = \frac{} {} v\sin \left(\theta\right) t - \frac{1} {2} g t^2$

By applying the quadratic formula

$\frac{} {}t = 0$

$t = \frac{2 v \sin \theta} {g}$

$x = \frac {2 v^2 \cos \left(\theta\right) \sin \left(\theta\right)} {g}$

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gOlU g3n|[0]uS

15 Years ago

deeksha sharma

15 Years ago

To Golu

what you solved was "If a man can throw till max height H, then with same velocity he can throw maximum about 2H long"

whereas the question is simply demanding for the derivation of max range in oblique projection of projectile.

gOlU g3n|[0]uS

15 Years ago

hi deeksha then PLZ tell me wright SOL. and correct my mistake

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if a particle is projected from hight H with velocity v & angle ω, what is its maximum range?

shashank jyoti yadav

4 Answers

SAGAR SINGH - IIT DELHI

gOlU g3n|[0]uS

deeksha sharma

gOlU g3n|[0]uS

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