Dear Sneha,
ANS:-Let the velocity of the masses when the spring is again totally relaxesd is v, Then from the energy eq we get
1/2kd²=1/2(M1+M2)v²+(M1+M2)gdsinθ
Putting d=2/k(M1+M2)gsinθ & Solving we get v=0.
Hence the velocity is o, So, it will again compress the spring and let the comp is x then from energy eq we get,
(M1+M2)gsinθ x=1/2kx²
So again x=2(M1+M2)gsinθ/k
So, the two mass will execute Periodic motion with amplitude (M1+M2)gsinθ/k
THUS THEY WILL NEVER SEPARATE OUT
Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.
All the best Sneha!!!
Regards,
Askiitians Experts
SOUMYAJIT IIT_KHARAGPUR
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
Last Activity: 9 Months ago
A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
11
21
31
41
Last Activity: 10 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
