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The speed of a projectile when it is at its greatest height is (2/5)raised to the power 1/2 times its speed at half the maximum height.The angle of projection is?

UMME AIMAN , 14 Years ago
Grade 12
anser 2 Answers
Chetan Mandayam Nayakar

Last Activity: 14 Years ago

ucos(theta) = (√(2/5))(√((u2cos2(theta)+(u2sin2(theta)-(2gu2sin2(theta)/4g))))

thus, cos(theta)= sqrt((1+(cos(theta))^2)/5)

thus theta = 60 degrees

Rahul

Last Activity: 6 Years ago

V(t)=complete ✓10sqr+gt(sqr}125=100+g(sqr)× t(sqr)T(sqr=125-100/100T(sqr)= 25/100So t=0.5Thus itvis the wrie akbeosbqkby rahul mahech if any mistake in this question tell me

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