Grade 12Mechanics
Plz solve hc verma , vol 1 –Pg 10 No. 19…
Plz solve hc verma , vol 1 –Pg 10 No. 19…
1 Answer
askiitian expert akshay singh
hi,
let me make clear inregral is just summation so its not gonna effect dimensions of term inside integral sign. Integral of dx/√ a2-x2 is 1/a( sin-1 x/a),dimension of dx is L,and that of √ a2-x2 is also L therefore dx/√ a2-x2 is dimensionless and on the R.H.S 1/a has L-1 dimension and sin-1 term is dimensionless,therefore L.H.S is dimensionless and R.H.S is L-1 ,so The eq. is not correct dimensionally.
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