Plz solve hc verma , vol 1 –Pg 10 No. 19…

hi,

let me make clear inregral is just summation so its not gonna effect dimensions of term inside integral sign. Integral of dx/√ a²-x²   is 1/a( sin^-1 x/a),dimension of dx is L,and that of √ a²-x² is also L therefore dx/√ a²-x² is dimensionless and on the R.H.S 1/a has L^-1 dimension and sin^-1 term is dimensionless,therefore L.H.S is dimensionless and R.H.S is L^-1 ,so The eq. is not correct dimensionally.