Rahul askIITiansExpert.IITR
Last Activity: 14 Years ago
since the collision is elastic velocity along the common normal interchanges and along the incline remains same.
theresfore velocity along incline= and along normal =
so distance along the incline=............1
distance along normal==0
this gives t as 2v/g where v=
substitute this in 1 to get the answer
the answer should be
please approve