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In first case, two masses of 1 KG and 2KG are present on opposite sides{ends} of the frictionless pulley. In second case, a mass of 1KG is on one side and 20 N force is applied on the other side of the pulley. What is the difference between the two situations?? PLS EXPLAIN where it matters....... {TAKE g = 10 m/ sec2}
In first case, two masses of 1 KG and 2KG are present on opposite sides{ends} of the frictionless pulley.
In second case, a mass of 1KG is on one side and 20 N force is applied on the other side of the pulley.
What is the difference between the two situations?? PLS EXPLAIN where it matters.......
In first case, net force along 2kg block is 20-10=10N. This force causes acceleration of total mass 1+2=3Kg. But, in second case, net force being same, total mass is 1 Kg only. Hence, acceleration is more is second case..... Here is the difference between two situations....
See in the first case , the net force is 20-10 = 10 N and the net mass is 2+1 = 3 kg, Hence the acc. in the first case is 10/3 m/s^2.
In the second case the net force is again 20-10 - 10 N but here the net mass to be moved is only 1 kg . Hence the acc. in this case is 10/1 = 10 m/s^2
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