A ball is projected from top of the tower with a velocity of 5 m/s at an angle 53 to horizontal. Its speed when it is at height of 0.45 m from point of projection is...................

Dear Vishrant

Ans:- The vertical component of the velocity= 4 m/s

         The horizental component is=3m/s

The final vertical velocity is=√(4² - 2*g*0.45) m/s

                                    =√(16-9)

                                     =√7 m/s

The horizental component is is same = 3m/s

Hence the total speed is=√(9+7)=4m/s(ans)

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