My Question is:

A train has to negotiate a curve of 250m. By how much should the outer rail be raised with respect to the inner rail for a speed of 54 km/hr ? the distance between the rails is 1.2m. Take g=10m/s2

I am unable to get the formula to solve this.

Thank You.

DearChinmayi Karmalkar,

Ans; Draw the FBD of the problem. let N be the normal reaction and the horizontal part of which gives the centipetal Accn. Hence the eq of motion are

N sinθ=mv²/r

N cosθ=mg

Hence tanθ=v²/rg

Putting the values we get that tanθ=0.09

Let the height of the outer track is=x Then tanθ=x/1.2

So x=0.108 m(ans)

Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.

All the best Chinmayi Karmalkar!!!

Regards,

Askiitians Experts

SOUMYAJIT IIT_KHARAGPUR