Grade 12th passMechanics
1 and 2..............................................................................................
1 and 2..............................................................................................
1 Answer
Arun
Dear Shivam
please ask only one question in one thread.
1.)
Apply second law of eqn. in y- direcn. .i.e.
90 = 100*t – 0.5*g*t^2
solving we get t=1 and t= 19 s but t= 1 is perceived.
In this 1 s he would miss the deer.
So to hit it, he needs extra => 0.5*g*1^1 = 5 meter above the deer.
Regards
Arun (askIITians forum expert)
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