Grade 12th passMechanics

(1)a particle moves in a straight line with constant speed 4m/s for 2sec. then with 6m/s for 3sec. find the av.speed of the particle in the given time interval.

sanjeev rana

8 Years agoGrade 12th pass

2 Answers

sreehari

8 Years ago

Distance Travelled = Speed x Time taken.

Avg Speed = (Total Distance travelled)/(Total Time taken)

In (1);

Distance Travelled = 4 x 2 = 8 m.

In (2);

Distance Travelled = 6 x 3 = 18 m.

Total Distance Travelled = 26 m.

Hence, Average speed = 26/5 = 5.2 m/sec

Adarsh

5 Years ago

Speed= distance/time so in the first case

4=d₁/2 so d₁= 8m

In the second case using speed formula

6=d₂/3 so d₂=18m

Total distance= d₁+d₂=18+8=26

Total time =2+3=5. (Time is given in the question)

Average speed= total distance/total time= 26/5 =5.2 m/s

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(1)a particle moves in a straight line with constant speed 4m/s for 2sec. then with 6m/s for 3sec. find the av.speed of the particle in the given time interval.

sanjeev rana

2 Answers

sreehari

Adarsh

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