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`        0.4i^+0.8j^+bk^ is unit vector.  ,what is the value of b?`
5 months ago

Vikas TU
9476 Points
```							Hiii Alisa for a unit vector , its magnitude should be equal to 1.so here we will find the magnitude of vector and put that equal to 1.so square root (0.42+0.82+b2) = 1the value of b would be 0.44Hope this helps.
```
5 months ago
Jiya
13 Points
```							Unit vector means its magnitude is equal to 1so magnitude:(0.4^2 +0.8^2 + b^2) = 1(0.16 + 0.64 + b^2) = 1(0.80 + b^2) = 1B^2 = 1- 0.8b^2 = 0.2b= 0.2 ^ 1/2
```
5 months ago
Harsh
47 Points
```							Unit vector is a vector whose magnitude is equal to oneHence(0.4)²+(0.8)²+(b)²=11.6+6.4+b²=1b²=1-0.8=0.2
```
4 months ago
Khimraj
3008 Points
```							Unit vector means magnitude of vector is unity .1=root {(0.4)^2+(0.8)^2+(b)^2} take square both side 1=0.16 +0.64 +b^2b^2 =0.2b=+_0.45
```
3 months ago
aswanth nayak
68 Points
```							Dear student,   Since it is a unit vector, it's magnitude = 1.(0.4)²+(0.8)²+(b)²=11.6+6.4+b²=1b²=1-0.8=0.2Hope this helps you Regards
```
3 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions