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Two particles of equal mass move around a circle of radius R under the action of their mutual gravitational attraction.What is the speed v of each particle?

hridya p , 10 Years ago
Grade 12
anser 1 Answers
Nirmal Singh.

Last Activity: 10 Years ago

Both mass will move with equal velocity the mutual gravitational attraction force with be equal to centripetal force


so Gmm / (2R)^2 = mv^2 / R

On solving v = sqrt (Gm / 4R^3)

Regards,
Nirmal Singh
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