0

Guest

Courses New

A calorimeter of specific heat 0.42j/qxm℃ Weighing 40qxm contains 50qxm of water mixed with 50qxm of ice. Steam at 100℃ is passed into the mixture until the temp rises to 20℃. Find mass of steam condensed.take Of=80cal/qxm Lv=540cal/qxm and J =4.2j/cal .

A calorimeter of specific heat 0.42j/qxm℃
Weighing 40qxm contains 50qxm of water mixed with 50qxm of ice. Steam at 100℃ is passed into the mixture until the temp rises to 20℃. Find mass of steam condensed.take Of=80cal/qxm 
Lv=540cal/qxm and J =4.2j/cal .

Grade:12th pass

1 Answers

Aditya Pathak
44 Points
5 years ago
Q1= mlv +ms∆t 
=m(540)+m(80)=m(620)
Mixture = 40qxmcal+50qxmwater+50qxm of ice )
= mc.sc(20)+me.sw(20)+milf +misw(20)
Where lf is latent heat of fussion 
Heat required for 0℃to 20℃ rise
= 40×0.42/j×20+50×20+50×80+50×20
80+1000+4000+1000=6080=m(620)
M=9.8 qxm 
I hope your help
Heat required for 0

Think You Can Provide A Better Answer ?

Other Related Questions on Marks and Rank in IIT JEE

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More