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`        A calorimeter of specific heat 0.42j/qxm℃Weighing 40qxm contains 50qxm of water mixed with 50qxm of ice. Steam at 100℃ is passed into the mixture until the temp rises to 20℃. Find mass of steam condensed.take Of=80cal/qxm Lv=540cal/qxm and J =4.2j/cal .`
one year ago

44 Points
```							Q1= mlv +ms∆t =m(540)+m(80)=m(620)Mixture = 40qxmcal+50qxmwater+50qxm of ice )= mc.sc(20)+me.sw(20)+milf +misw(20)Where lf is latent heat of fussion Heat required for 0℃to 20℃ rise= 40×0.42/j×20+50×20+50×80+50×2080+1000+4000+1000=6080=m(620)M=9.8 qxm I hope your helpHeat required for 0
```
one year ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions