P(a, b) is a point in the first quadrant. If the two circles which pass through P and touch both the coordinate axes cut at right angles, then (a) a2 – 6ab + b2 = 0 (b) a2 + 2ab – b2 = 0 (c) a2 – 4ab + b2 = 0 (d) a2 – 8ab + b2 =

Dear Nilmani,

The correct answer is a;

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