whn we convert galvanometer to ammeter we add a shunt to it. d shunt lowers the resistance of the circuit. again as d shunt resistance is very low as compared to that of d galvanometer, only a fraction of current passes thru d galvanometer.
so, my doubt is that- since only a little amount of current is passed thru galvanometer, then how do we obtain the correct reading of current??? (consider the case of moving coil galvanometer).
plz explain using formulae......
rates assured.....
whn we convert galvanometer to ammeter we add a shunt to it. d shunt lowers the resistance of the circuit. again as d shunt resistance is very low as compared to that of d galvanometer, only a fraction of current passes thru d galvanometer.
so, my doubt is that- since only a little amount of current is passed thru galvanometer, then how do we obtain the correct reading of current??? (consider the case of moving coil galvanometer).
plz explain using formulae......
rates assured.....
Navjyot Kalra , 11 Years ago
Grade 10
