what willbe the magnetic field at the center of a current carrying circular coil carrying current I . and why?

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Ashwin · Answer

since magnetic field at any point P on the axis of circular current carring coil is B = ( µ 0 iR 2) / (2[R 2 + X 2 ] 3/2) where R :- Radius of coil i = current x = sepration of point from centre but now since at the centre of coil we have x = 0 there fore B center = µ 0 i / 2R

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what willbe the magnetic field at the center of a current carrying circular coil carrying current I . and why?

what willbe the magnetic field at the center of a current carrying circular coil carrying current I . and why?

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