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Two small magnets each of magnetic moment 10A-m^2 are placed in end on position 0.1m apart from their centres. The force acting between them will me? 0.6N 0.06N 0.06*10^7 N 0.6*10^7 N. [AP ch8 pg 76 Q59]

ANMOL SETH , 10 Years ago
Grade 12th pass
anser 1 Answers
Unni

Last Activity: 5 Years ago

Formula for force BT parallel placed magnet f=Mo/4π(6m1m2/r4)
No=4π×10^-7 therefore f=10^-7(6×10×10/(0.1^4)=0.6N

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