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Dear studet
B = mo * I / 2 * pi * r = 10^-7 * 2 * 10 / 2 * 10^-2
B = 10^-4 T
So net is [(10–4)2 + (10–4)2 + 2(10–8) Cos 60°]1/2
= 10–4[1 + 1 + 2 × ½ ]1/2 = 10-4 × √3 T = 1.732 × 10–4T
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