MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
Two moving coil meters have the following particulars:
R1 = 10 Ω , N 1 = 30, A1 = 3.6 × 10−3 m 2 , B1 = 0.25T R2 = 10 Ω , N 2 = 42, A2 = 1.8 × 10−3 m 2 , B2 = 0.50T
The spring constants are identical for the two meters. Determine the ratio of
(i) Current sensitivity and (ii) Voltage Sensitivity of M 2 and M1 .
Current Sensitivity
 
9 months ago

Answers : (1)

srikanth vadagam
12 Points
							
α
I

=
NBA
k
Current sensitivity of M 2
N B A / k N 2 B2 A2 42 × 0.50 × 1.8 × 10−3
= 2 2 2
=
=
= 1.4
Current sensitivity of M 1
N1 B1 A1 / k
N1 B1 A1
30 × 0.25 × 3.6 × 10−3
Voltage sensitivity
α
V
=
α
IR
=
NBA
kR
Voltage sensitivity of M 2 N 2 B2 A2 / kR2 N 2 B2 A2 R1 7 10
=
=
×
= × =1
Voltage sensitivity of M 1
N1 B1 A1 / kR1
N1 B1 A1 R2 5 14
 
 
9 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details