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Two concentric circular coils A and B have radii 25cm and 15cm and carry currents 10A and 15A respoectively.A has 24 turns and B has 18 turns.the direction of the currents are in opposite order . the magnetic induction at the common center of the coil is ?
for coil A: VA=25cm=0.25mnA=24nA=24IA=10AI=10AFor coil B:rb=15cm=0.15mnb=18nb=18Ib=15AI=15AMagnetic field at the center of coil xBA=µ0 /4π*2Ia πna/ra=10−7×2×10×3.14×24/0.25=6.028×10^−4=6.028×10^−4TMagnetic field at the center of coil BB= µ0 /4π*2Ib πnb/rb=10−7×2×3.14×15×18=11.30×10−4THence the net magnetic field at the centerBb−Ba=(11.30×10−4−6.028×10−4)T=5.27×10−4T
for coil A:
VA=25cm=0.25m
nA=24nA=24
IA=10AI=10A
For coil B:
rb=15cm=0.15m
nb=18nb=18
Ib=15AI=15A
Magnetic field at the center of coil x
BA=µ0 /4π*2Ia πna/ra
=10−7×2×10×3.14×24/0.25
=6.028×10^−4
=6.028×10^−4T
Magnetic field at the center of coil B
B= µ0 /4π*2Ib πnb/rb
=10−7×2×3.14×15×18
=11.30×10−4T
Hence the net magnetic field at the center
Bb−Ba=(11.30×10−4−6.028×10−4)T
=5.27×10−4T
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