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There are two homogenous parallel magnetic fields B1 and B2... a charged particle flies into the the fields with velocity v perpendicular to both fields at the perpendicular between two fields (labelled x-axis)... thereon it has an average velocity vx along that axis.

What is the relation between the two fields B1 and B2? Following pic may clarify the situation:


[IMG]http://i32.tinypic.com/2whov0m.jpg[/IMG]


Answer given is:

B2 2v + pi * vx
---- = ----------------
B1 2v - pi * vx

How to solve?



Aditi Chauhan , 12 Years ago
Grade 10
anser 1 Answers
Askiitians Tutor Team

To understand the relationship between the two magnetic fields, B1 and B2, when a charged particle enters them with a specific velocity, we need to analyze the forces acting on the particle and how they interact with the magnetic fields. The scenario you've described involves a charged particle moving perpendicular to two homogeneous magnetic fields, which creates a complex motion due to the Lorentz force. Let's break this down step by step.

Understanding the Forces at Play

When a charged particle moves through a magnetic field, it experiences a force known as the Lorentz force, which is given by the equation:

F = q(v × B)

Here, F is the force, q is the charge of the particle, v is its velocity, and B is the magnetic field. The direction of this force is perpendicular to both the velocity of the particle and the magnetic field direction.

Analyzing the Motion

In your scenario, the particle enters the magnetic fields with a velocity v that is perpendicular to both B1 and B2. This means that the particle will experience forces from both magnetic fields. The net effect of these forces will determine the particle's trajectory and average velocity along the x-axis.

Setting Up the Equations

Let's denote the forces due to the magnetic fields as follows:

  • Force due to B1: F1 = q(v × B1)
  • Force due to B2: F2 = q(v × B2)

Since the particle is moving in a plane defined by the two magnetic fields, we can analyze the components of the forces. The average velocity along the x-axis, denoted as vx, will be influenced by the balance of these forces.

Deriving the Relationship

To derive the relationship between B1 and B2, we can consider the net force acting on the particle. The forces from the two magnetic fields will affect the particle's motion in such a way that:

F1 + F2 = 0

This implies that the forces must balance out for the particle to maintain a steady average velocity vx along the x-axis. Therefore, we can express the relationship between the two magnetic fields in terms of their magnitudes and the velocities involved.

Using the Given Equation

The equation you provided:

B2(2v + πvx) = B1(2v - πvx)

can be rearranged to find the relationship between B1 and B2. Let's isolate B2:

B2 = (B1(2v - πvx)) / (2v + πvx)

This equation shows how B2 is dependent on B1, the velocities, and the interaction between the two magnetic fields. The terms involving π and the velocities indicate how the average velocity vx modifies the influence of the magnetic fields on the charged particle.

Conclusion

In summary, the relationship between the two magnetic fields B1 and B2 is derived from the balance of forces acting on the charged particle as it moves through the fields. The equation you provided encapsulates this relationship, showing how the average velocity vx and the magnitudes of the magnetic fields interact. Understanding this interplay is crucial in fields like electromagnetism and particle physics, where charged particles are influenced by magnetic fields in various applications.

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