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The strength of magnetic induction at the centre of current carrying coil is given at at a point on its Axis at a distance equal to its ladies wrote this letter is B to find B1 by B2

The strength of magnetic induction at the centre of current carrying coil is given at at a point on its Axis at a distance equal to its ladies wrote this letter is B to find B1 by B2

Grade:12

1 Answers

Arun
25758 Points
4 years ago
Dear Keshav
Magnetic field dueto current carrying coil is given by
B = (u0nI/2)(r2/(x2+r2)3/2)
For B1 x =0
So B1 =(u0nI/2r)
for B2 x= r
So B2 = (u0nI/25/2r)
So B1/B2 = 23/2.
Hope it clears.
Regards
Arun (askIITians forum expert)

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