The strength of magnetic induction at the centre of current carrying coil is given at at a point on its Axis at a distance equal to its ladies wrote this letter is B to find B1 by B2

Question

Arun · Answer

Dear Keshav Magnetic field dueto current carrying coil is given by B = (u 0 nI/2)(r 2 /(x 2 +r 2 ) 3/2 ) For B1 x =0 So B1 =(u 0 nI/2r) for B2 x= r So B2 = (u 0 nI/2 5/2 r) So B1/B2 = 2 3/2 . Hope it clears. Regards Arun (askIITians forum expert)

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The strength of magnetic induction at the centre of current carrying coil is given at at a point on its Axis at a distance equal to its ladies wrote this letter is B to find B1 by B2

The strength of magnetic induction at the centre of current carrying coil is given at at a point on its Axis at a distance equal to its ladies wrote this letter is B to find B1 by B2

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The strength of magnetic induction at the centre of current carrying coil is given at at a point on its Axis at a distance equal to its ladies wrote this letter is B to find B1 by B2

The strength of magnetic induction at the centre of current carrying coil is given at at a point on its Axis at a distance equal to its ladies wrote this letter is B to find B1 by B2

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