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The potential energy of a bar magnet of magnetic moment 8 am square placed in a uniform magnetic field of 2 T at an anglr of 120° is equal to

The potential energy of a bar magnet of magnetic moment 8 am square placed in a uniform magnetic field of 2 T at an anglr of 120° is equal to

Grade:12th pass

2 Answers

Mahima Kanawat
1010 Points
3 years ago
Dear student....as we know potential energy of magnetic dipole in uniform magnetic field = - MBcosΘ .....PE= - 8×2×cos120°= - 16× (-1/2)= +8 J.....With Regards....Mahima....(Askiitians Forum Expert )
Khimraj
3007 Points
3 years ago
The potential Energy of a magnetic dipole placed in magnetic field is given by 
PE = - MBcosΘ 
where M is magnetic moment 
B is magnetic field strength
and Θ is angle between dipole and magnetic field.
So PE = -8*2*cos1200 =  8.
Hope it clears.

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