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the magnetic induction field due to a north pole of strength 10Am and 5cm away from the pole in weber/msquare

yashwanth chinnu , 7 Years ago
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anser 2 Answers
Samyak Jain
Magnitude of magnetic induction due to a pole of strength m at a distance r from it is
B = (\mu0 / 4\pi)(m / r2) ,     \mu0 / 4\pi = 10–7 H.
m = 10 Am,  r = 5 cm = 5 x 10–2 m
So, magnitude of magnetic induction, B = (10–7)(10 / 25 x 10–4)  =  4 x 10–12 Wb / m2.
Last Activity: 7 Years ago
Samyak Jain
There is a slight mistake in calculation. The magnitude of magnetic induction should be
B = 4 x 10–4 Wb / m2.
Last Activity: 7 Years ago
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