Flag Magnetism> The horizontal component of earth's magne...
question mark

The horizontal component of earth's magnetic field is 3x10^-5 T, the direction of the field is from the geographic south to the geographic north. Along it a long staraight conducter is carrying a steady current of 1A. Calculate the force per unit length on it when it is plced horizontally and the direction of the current is from east to west.

Jitender Pal , 12 Years ago
Grade 9
anser 1 Answers
Askiitians Tutor Team

To find the force per unit length on a straight conductor carrying a current in a magnetic field, we can use the formula derived from the Lorentz force law. The force \( F \) on a conductor of length \( L \) carrying a current \( I \) in a magnetic field \( B \) is given by:

Formula for Magnetic Force

The formula for the magnetic force per unit length \( f \) is expressed as:

f = B \cdot I \cdot \sin(\theta)

Where:

  • f = force per unit length (N/m)
  • B = magnetic field strength (T)
  • I = current (A)
  • θ = angle between the direction of the magnetic field and the direction of the current (degrees)

Given Values

In this scenario:

  • The magnetic field strength \( B = 3 \times 10^{-5} \, \text{T} \)
  • The current \( I = 1 \, \text{A} \)
  • The direction of the magnetic field is from geographic south to geographic north.
  • The current flows from east to west.

Determining the Angle

Since the magnetic field is directed from south to north and the current is directed from east to west, the angle \( θ \) between the magnetic field and the current direction is \( 90^\circ \). The sine of \( 90^\circ \) is 1, which simplifies our calculations:

sin(θ) = sin(90°) = 1

Calculating the Force per Unit Length

Now we can substitute the values into the formula:

f = B \cdot I \cdot sin(θ)

Substituting the known values:

f = (3 \times 10^{-5} \, \text{T}) \cdot (1 \, \text{A}) \cdot (1)

f = 3 \times 10^{-5} \, \text{N/m}

Direction of the Force

To determine the direction of the force, we can use the right-hand rule. Point your thumb in the direction of the current (east to west) and your fingers in the direction of the magnetic field (south to north). Your palm will then face upwards, indicating that the force on the conductor is directed upwards.

Summary

The force per unit length on the conductor is 3 x 10^-5 N/m, and the direction of the force is upwards.

ApprovedApproved
Last Activity: 10 Months ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments