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Solve this question based on magnetic field of a finite straight wire

Syed suha , 7 Years ago

Grade 12

2 Answers

Eshan

We need to find the angles the lines OP and OQ form with OM. Let them be $\theta_1$ and $\theta_2$ , respectively.

From trigonometry, $tan\theta_1=\dfrac{3}{4}\implies sin\theta_1=\dfrac{3}{5}$
and $tan\theta_2=\dfrac{4}{3}\implies sin\theta_2=\dfrac{4}{5}$

Hence magnetic field at point O= $\dfrac{\mu_0i}{2\pi a}\dfrac{sin\theta_1+sin\theta_2}{2}$
$=\dfrac{\mu_0i}{4\pi a}$

Last Activity: 7 Years ago

Khimraj

Magnetic field due to a wire of finite length is given by

B = (u_oI/4 $\pi$ r)(sin $\Theta 1$ + sin $\Theta 2$ )

where $\Theta 2$ is angle QOM

and $\Theta 1$ is angle POM

r is perpendicular distance

So B = (u_oI/4 $\pi$ a)(3/5 + 4/5)

So B = (7/20)u_oI/ $\pi$ a.

Hope it clears. If you like answer then please approve it.

Last Activity: 7 Years ago

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