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Solve this problem please........................................

Solve this problem please........................................

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Grade:12

2 Answers

Khimraj
3007 Points
5 years ago
Magnetic field due to a wire of finite length is given by
B = (uoI/4\pir)(sin\Theta 1 + sin\Theta 2)
where \Theta 2 is angle QOM
and \Theta 1 is angle POM
r is perpendicular distance
So B = (uoI/4\pia)(5a/3 + 5a/3)
So B = (5/6)uoI/\pia.
Hope it clears. If you like answer then please approve it.
Khimraj
3007 Points
5 years ago
Magnetic field due to a wire of finite length is given by
B = (uoI/4\pir)(sin\Theta 1 + sin\Theta 2)
where \Theta 2 is angle QOM
and \Theta 1 is angle POM
r is perpendicular distance
So B = (uoI/4\pia)(3/5 + 4/5)
So B = (7/20)uoI/\pia.
Hope it clears. If you like answer then please approve it.

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