Solve this problem please........................................
Syed suha , 6 Years ago
Grade 12
Magnetism> Solve this problem please...................
2 Answers
Khimraj
Last Activity: 6 Years ago
Magnetic field due to a wire of finite length is given by
B = (uoI/4
r)(sin
+ sin
)
where is angle QOM
and is angle POM
r is perpendicular distance
So B = (uoI/4a)(5a/3 + 5a/3)
So B = (5/6)uoI/a.
Hope it clears. If you like answer then please approve it.
Khimraj
Last Activity: 6 Years ago
Magnetic field due to a wire of finite length is given by
B = (uoI/4r)(sin + sin)
where is angle QOM
and is angle POM
r is perpendicular distance
So B = (uoI/4a)(3/5 + 4/5)
So B = (7/20)uoI/a.
Hope it clears. If you like answer then please approve it.
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