When the bar is bent we need to consider the eff length between 2 poles. Let the radius of the semicircle be r . So pi r = l. Now previously M= m*l Now newM= m*2r. And r= l/pi. So newM= 2M/pi
Last Activity: 5 Years ago
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.