# Ques.1>  A capacitor of capacitance 10microfarad is charged to a potential of 1V. It is connected to an inductor of inductance 10 raise to power -3 H. The maximum current that will flow in the circuit has the value -a> 1 micro ampereb> 1 milli amperec> under root 1000 milli ampered> 100 milli AmpereQues 2> In a region of uniform magnetic induction B = 10 raise to the power -2 T, a circulaer coil of radius 30cm and resistance pie square ohm is rotatted about an axis which is diameter of the coil. If the coil rotates at 200rpm, the amplitude of the alternating current induced in the coil isa> 4 pie square milli ampereb> 30 milli amperec> 6 milli ampered> 200 milli ampereQues.3> A circular coil of raidus 0.1 m has 80 turns of wire. If the magnetuc field thorugh the coil increases from 0 to 2 tesla in 0.4 sec and the coil is connected to a 11 ohm resistor, what is the current (in A) through the resisitor during the 0.4 sec?a> (8/7) Ab> (7/8) Ac> 8 Ad> 7 APlease help me with complete solutions need them URGENTLY..Thanks in advance.. will rate u for help!!Rohit

ROSHAN MUJEEB
4 years ago
Time period for oscillating magnet is
T=2πMBI​.........(1)
where I is the moment of inertia,

M is the magnetic moment
M=x×l
x=polestrength
When the magnet is broken in two equal parts, the new magnetic dipole moment is
M′=2x×l​=2M​
I′=2ML12​
=122M​×(2L​)2​
=12×8ML2​
=8I​
New time period is
T′=2πM′BI′​
TT′​=M′I′​
Putting all the values we get
TT′​=41​​=21​