Q. The magnetic in a certain region of space is given by- B = 8.35 * 10 -2 j ^ T. A proton is shot intothe field with velocity v= ( 2 * 10 5 i ^ + 4 * 10 5 j ^ ) The proton follows a helical path in the field. The distance moved by proton in the x- direction during the period of one revolution in the yz- plane will be- 1. 0.053m 2. 0.136m 3. 0.157m 4. 0.236m

Question

​Q. The magnetic in a certain region of space is given by- B = 8.35 * 10 -2 j ^ T. A proton is shot intothe field with velocity v= ( 2 * 10 5 i ^ + 4 * 10 5 j ^ ) The proton follows a helical path in the field. The distance moved by proton in the x- direction during the period of one revolution in the yz- plane will be- 1. 0.053m 2. 0.136m 3. 0.157m 4. 0.236m

deepak · Answer

first let us understand the motion of the particle, F = q X hence force is going to be towards the hence the particle will have circular motion in the x-z plane and translatory motion along the y direction hence the distance moved along the x direction will be the radius of the helix, we know that the radius of the helix = MV / BQ …....where m is mass of the proton q is its charge v is its velocity along the x direction ( only the i component) and B is the magnetic field strength =>r = 0.0236 m the answer resembles option 4 pls check whether you have correctly given the information hope this helps XD

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