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​Q. The magnetic flux through a coreless solenoid carrying current I is 5*10-6 Wb. The length of the solenoid is 25cm. What is its magnetic moment ?

Naina Singh , 8 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Flux = B.dA
where dA is the area associated with the flux.
Therefore,
5*10^6 = 0.25*B
B = 2 x 10^7 T would be the magnetic moment.

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