Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

​​Q. A planar coil having12 turns carries 15A current. The coil is oriented with respect to the uniform magetic field B =0.2 i ^ T. such that its directed area is A = -0.04 i ^ m 2 . The potential energy of the coil in the given orientation is what ?

​​Q.   A planar coil having12 turns carries 15A current. The coil is oriented with respect to the uniform magetic field  B =0.2 i^ T. such that its directed area is A = -0.04 i^ m2.    The potential energy of the coil in the given orientation is what ? 

Grade:12th pass

1 Answers

deepak
84 Points
4 years ago
as you know a coil in a magnetic field only experiences torque, and
 
\overrightarrow{T} = \overrightarrow{M} X \overrightarrow{B}   where T is torque , M is magnetic dipole moment and B is magnectic field
 
we know that
\overrightarrow{M} = NI\overrightarrow{A}  where N is the no of turns i is the current and A is the areal vector
\overrightarrow{M}=12x15x(-0.04 \widehat{i})
 
also \overrightarrow{B}=0.2\widehat{i}
 
 
now consider ,
\overrightarrow{T} = \overrightarrow{M} X \overrightarrow{B}    => T=MBsin \Theta
 
we know that workdone by torque,
 
W.D = \int T*d\Theta
 
 
W.D = \int MB sin\Theta * d\Theta
 
therefore
 
W.D=− MB cos\Theta
W.D= −\overrightarrow{M}.\overrightarrow{B}
 
substituting the value of M and B
 
W.D = P.E = +12x15x0.2x0.004 = 0.144 J
 
 
hope this was usefull XD
 
 
 
 
 
 
 
 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free