#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Q.   A closely wound solenoid80cm long has 5 layers of winding of400 turns each.  The diameter ofthe solenoidis 1.8cm.  If the current carried is 8A, the magnitude of B inside the solenoid near its centre will be-                                                    1. 8pie*10-3T          2. 6pie*10-3T        3. 4pie*10-3T          4. 3pie*10-3T

deepak
84 Points
4 years ago
magnetic field due to a solenoid is = B= $\eta n I$   …...here n is the winding density I is the current $\eta$ is the permiability of free space

=>B = 5 x 4$\pi$x 10-7 x (400/0.8) x 8    here 5 is multiplied as 5 layers are present
=>B = 8$\pi$x10-3 T

dosent this answer seem satisfying but actually logically this is wrong the maker of this question must be an idiot who dosent know physics just think logically no..  let current thru  the 1st layer be towards the right hand side then the current in the 2nd layer should be in the left hand direction hence the field by the two layers should cancel out  then only one layer will contribute to  the magnetic field then the answer would be 16$\pi$x10-4   T... hence the idiot who made this question should have mentioned the way of winding
cause the direction of winding changes the answer totally ..

P.S so understand the concepts completly to shine in physics and parctise a lot hope this is helpful ;)