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please see the image......

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Grade:12

1 Answers

Abhishek Kumar
askIITians Faculty 253 Points
6 years ago
Force on the two horizontal part of the bend acts in the -Y direction.
Since the force on the two bends is in the same direction, we don’t need to specifically know the separate lengths. The formula is,
F1= BIL
Or,
If we let the first bend of length X, then rest horizontal bend is (0.6-X)
F1= BIX + BI(0.6-X) = BIL
So, F1=0.240*4.5*0.6 = 0.648 N in -Y direction.
For the vertical bend,
F2 = 0.240*4.5*0.3 = 0.324 N in X- direction.
So, Net Force = sqrt(F12 + F22) = 0.724 N
Angle = tan inverse(0.648/0.324) = 63.4 degree below x- axis

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