please see the image......

Force on the two horizontal part of the bend acts in the -Y direction.
Since the force on the two bends is in the same direction, we don’t need to specifically know the separate lengths. The formula is,
F₁= BIL
Or,
If we let the first bend of length X, then rest horizontal bend is (0.6-X)
F₁= BIX + BI(0.6-X) = BIL
So, F₁=0.240*4.5*0.6 = 0.648 N in -Y direction.
For the vertical bend,
F₂ = 0.240*4.5*0.3 = 0.324 N in X- direction.
So, Net Force = sqrt(F₁² + F₂²) = 0.724 N
Angle = tan inverse(0.648/0.324) = 63.4 degree below x- axis