Grade 12th passMagnetism

Magnetic moment of a bar magnet is M. the work done to turn the magnet by 90 degrees of magnet in direction of magnetic field B will be

1 Answer

Torque acting on a body of magnetic moment $\vec{M}$ placed in a magnetic field $\vec{B}$ is $\vec{\tau}=\vec{M}\times \vec{B}=MB sin\theta$ .
Hence work done in turning bar magnetic from angle $\theta_1$ to $\theta_2$ is

$W=\int_{\theta_1}^{\theta_2}MBsin\theta d\theta=MB(cos\theta_1-cos\theta_2)$
Hence work done in turning bar magnet by $\90^{\circ}$ = $MB(cos0^{\circ}-cos90^{\circ})$ =MB

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Magnetic moment of a bar magnet is M. the work done to turn the magnet by 90 degrees of magnet in direction of magnetic field B will be

Achyuth Goud

1 Answer

Eshan

What is the diagram of NSOE when it goes from north to south over the magnet towards east

Four long co-axial thin walled cylindrical conductor A, B, C and D have radii R. 2R 3R and 4R respectively. A and C carry current I and 31 respectively to plane of paper on the other hand, B and D carry and 41 respectively outward to plane of paper. Then 21

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What is magnetic entropy change? For my knowledge, I know entropy is randomness or disorder. So here that magnetic refers to the magnetic dipole moments?

Magnetic moment of a bar magnet is M. the work done to turn the magnet by 90 degrees of magnet in direction of magnetic field B will be

Achyuth Goud

1 Answer

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