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Magnetic moment of a bar magnet is M. the work done to turn the magnet by 90 degrees of magnet in direction of magnetic field B will be

Achyuth Goud , 6 Years ago

Grade 12th pass

1 Answers

Eshan

Last Activity: 6 Years ago

Torque acting on a body of magnetic moment $\vec{M}$ placed in a magnetic field $\vec{B}$ is $\vec{\tau}=\vec{M}\times \vec{B}=MB sin\theta$ .
Hence work done in turning bar magnetic from angle $\theta_1$ to $\theta_2$ is

$W=\int_{\theta_1}^{\theta_2}MBsin\theta d\theta=MB(cos\theta_1-cos\theta_2)$
Hence work done in turning bar magnet by $\90^{\circ}$ = $MB(cos0^{\circ}-cos90^{\circ})$ =MB

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