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Grade 12th passElectromagnetic Induction

Magnetic moment of a bar magnet is M. the work done to turn the magnet by 90 degrees of magnet in direction of magnetic field B will be

Achyuth Goud

8 Years agoGrade 12th pass

3 Answers

Eshan

Approved Tutor Answer8 Years ago

Dear student,

Torque acting on a magnet of magentic moment $\vec{M}$ kept in an external magnetic field $\vec{B}$ is
$\vec{\tau}=\vec{M}\times \vec{B}=MBsin\theta$

Thus the work done in moving a magnet by $90^{\circ}$ in direction of magnetic field is
$W=\int_{90^{\circ}}^{0^{\circ}}MBsin\theta d\theta=MB(cos90^{\circ}-cos0^{\circ}) =-MB$

Gitanjali Rout

8 Years ago

$W=\int_{90^{\circ}}^{0^{\circ}}MBsin\theta d\theta=MB(cos90^{\circ}-cos0^{\circ}) =-MB$ in direction of magnetic field is $90^{\circ}$ Thus the work done in moving a magnet by $\vec{\tau}=\vec{M}\times \vec{B}=MBsin\theta$ is $\vec{B}$ kept in an external magnetic field $\vec{M}$ orque acting on a magnet of magentic moment

Khimraj

8 Years ago

Work done is given by

W = MB(cos0 – cos90) = MB.

Hope it clears.

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