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magnetic field is 37.2..at the center of the circular coil of radius 42cm..that has 100 turns is

magnetic field is 37.2..at the center of the circular coil of radius 42cm..that has 100 turns  is

Grade:12

2 Answers

SHANMUKESHWAR
461 Points
5 years ago
radius=42*10^-2
B=37.2
turns=100
B=4*3.14*I*100/2*42*10^-2
B=I*0.149*10^-3
I=37.2/0.149*10^-3
I=2.49*10^5A
Prabhakar ch
577 Points
5 years ago
Dear Sai kumar
                         Radius, R=42*10^-2
                         Magnetic field,  B=37.2
                         turns=100
                         B=4*3.14*I*100/2*42*10^-2
                         B=I*0.149*10^-3
                         I=37.2/0.149*10^-3
                         I=2.49*10^5A

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