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# Magnetic field at the centre of various regular polygons which are made by a constant length l current carrying wire as regular hexagon is???(assume side length a and direction of current anticlockwise)

Khimraj
3007 Points
3 years ago
Magnetic field at centre of n sided regular polygen is equal to n times of magnetic field due to one side.
B = n(uoI/4$\pi$r)(sin$\Theta 1$ + sin$\Theta 2$)
where r = acos$\Theta$ and $\Theta$1 = $\Theta$2
So B  = (nuoI/2$\pi$a)(tan$\Theta$)
$\Theta$ = $\pi$/n
where n is no side in regular polygen
Then
B = (nuoI/2$\pi$a)(tan($\pi$/n))
Hope it clears. If you like anser then please approve it.