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In the figure of the charge q is released at the origin. Find its x and y components of velocity as a function of time t and give the type of trajectory of the charged particle.

Given:
Electric field E acts along the +ve y axis and in xy plane there exists a uniform magnetic field B acting along +ve z axis. Mass of charged particle is m.


Ans:
Trajectory: Cycloid
vx=(E/B){1-cos(qBt/m)}
vy=(E/B)sin(qBt/m)

Deepak Patra , 11 Years ago
Grade upto college level
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