Magnetism> In the bohrmodel of hydrogen atom, the el...

In the bohrmodel of hydrogen atom, the electron circles around the nucleus with a speed 5×10^5 m/s In an orbit of radius 5×10^-11 m. What is the magnetic field at the centre of the orbit.
If possible can somebody please solve it using the formula B=mv/qr
Thank you

Kartik Sharma , 7 Years ago

Grade

2 Answers

Khimraj

AS B = mv/qr

m = 9.1*10^-31Kg

q = 1.6*10^-19 C

v = 5*10⁵ m/s

r = 5*10^-11 m

so B = 5.7*10⁴ T

Hope it clears.

Last Activity: 7 Years ago

Rohit

See as the electron revolves around the nucleus in circular path, velocity will be perpendicular to magnetic field. In this case CPetal force is balanced by magnetic Lorentz force.

So we get, B= mv/qr

Now Mass of electron= 9.1×10^-31 kg.

e = 1.6 × 10^-19 C( take only magnitude of e).

By substitution we get,

B = 5.69 × 10^4 T.

Hope it helps

Regards

Rohit.

Last Activity: 7 Years ago

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Magnetism> In the bohrmodel of hydrogen atom, the el...

In the bohrmodel of hydrogen atom, the electron circles around the nucleus with a speed 5×10^5 m/s In an orbit of radius 5×10^-11 m. What is the magnetic field at the centre of the orbit. If possible can somebody please solve it using the formula B=mv/qrThank you

Kartik Sharma , 7 Years ago

Khimraj

Rohit

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In the bohrmodel of hydrogen atom, the electron circles around the nucleus with a speed 5×10^5 m/s In an orbit of radius 5×10^-11 m. What is the magnetic field at the centre of the orbit.
If possible can somebody please solve it using the formula B=mv/qr
Thank you