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In the bohrmodel of hydrogen atom,  the electron circles around the nucleus with a speed 5×10^5 m/s In an orbit of radius 5×10^-11 m. What is the magnetic field at the centre of the orbit. 
If possible can somebody please solve it using the formula B=mv/qr
Thank you
one year ago

Answers : (2)

Khimraj
3008 Points
							
 
AS B = mv/qr
m = 9.1*10-31Kg
q = 1.6*10-19 C
v = 5*105 m/s
r = 5*10-11 m
so B = 5.7*104 T
Hope it clears.
one year ago
Rohit
84 Points
							
See as the electron revolves around the nucleus in circular path, velocity will be perpendicular to magnetic field. In this case CPetal force is balanced by magnetic Lorentz force.
So we get, B= mv/qr
Now Mass of electron= 9.1×10^-31 kg.
e = 1.6 × 10^-19 C( take only magnitude of e).
By substitution we get,
B = 5.69 × 10^4 T.
 
 
Hope it helps
Regards 
Rohit.
one year ago
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