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In the bohrmodel of hydrogen atom, the electron circles around the nucleus with a speed 5×10^5 m/s In an orbit of radius 5×10^-11 m. What is the magnetic field at the centre of the orbit. If possible can somebody please solve it using the formula B=mv/qrThank you
AS B = mv/qrm = 9.1*10-31Kgq = 1.6*10-19 Cv = 5*105 m/sr = 5*10-11 mso B = 5.7*104 THope it clears.
See as the electron revolves around the nucleus in circular path, velocity will be perpendicular to magnetic field. In this case CPetal force is balanced by magnetic Lorentz force.So we get, B= mv/qrNow Mass of electron= 9.1×10^-31 kg.e = 1.6 × 10^-19 C( take only magnitude of e).By substitution we get,B = 5.69 × 10^4 T. Hope it helpsRegards Rohit.
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