Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

In the bohrmodel of hydrogen atom, the electron circles around the nucleus with a speed 5×10^5 m/s In an orbit of radius 5×10^-11 m. What is the magnetic field at the centre of the orbit. If possible can somebody please solve it using the formula B=mv/qr Thank you

In the bohrmodel of hydrogen atom,  the electron circles around the nucleus with a speed 5×10^5 m/s In an orbit of radius 5×10^-11 m. What is the magnetic field at the centre of the orbit. 
If possible can somebody please solve it using the formula B=mv/qr
Thank you

Grade:

2 Answers

Khimraj
3007 Points
2 years ago
 
AS B = mv/qr
m = 9.1*10-31Kg
q = 1.6*10-19 C
v = 5*105 m/s
r = 5*10-11 m
so B = 5.7*104 T
Hope it clears.
Rohit
84 Points
2 years ago
See as the electron revolves around the nucleus in circular path, velocity will be perpendicular to magnetic field. In this case CPetal force is balanced by magnetic Lorentz force.
So we get, B= mv/qr
Now Mass of electron= 9.1×10^-31 kg.
e = 1.6 × 10^-19 C( take only magnitude of e).
By substitution we get,
B = 5.69 × 10^4 T.
 
 
Hope it helps
Regards 
Rohit.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free