Flag Magnetism> In a galvanometer there is a deflection o...
question mark

In a galvanometer there is a deflection of 10 divisions per mA. The internal resistance of the galvanometer is 78 ohm. If a shunt of 2 ohm is connected to the galvanometer and there are 75 divisions in all on the scale of the galvanometer,calculate the maximum current which the galvanometer can read.

Jitender Pal , 11 Years ago
Grade 9
anser 1 Answers
Samiksha

Last Activity: 6 Years ago

We will use the formula for calculating Imax of a Galvanometer, Ig = number of divisions/unit division
Ig = \frac{75}{10}, and, Imax = \frac{(Rg+Rs) Ig}{Rs} = \frac{(78+2) 75}{(78) 10} = \frac{100}{3}\boldsymbol{A}
Imax = \frac{(Rg+Rs) Ig}{Rs} = \frac{(78+2) 75}{(78) 10} = \frac{100}{3}\boldsymbol{A}

Provide a better Answer & Earn Cool Goodies

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free