If a particle of charge 10^-12C moving with velocity of 10^5 m/s experience a force of 10^-10 N in y direction due to magnetic field,then the minimum value of magnetic field is?

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Arun · Answer

Dear Rajit By Lorentz Force F = q * v* B sin@ Now B = F/q*v* sin@ For minimum magnetic field sin@ is maximum = 1 Hence B = 10 -10 /10 5 *10 -12 B = 10 -3 T in Z direction Regards Arun (askIITians forum expert)

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If a particle of charge 10^-12C moving with velocity of 10^5 m/s experience a force of 10^-10 N in y direction due to magnetic field,then the minimum value of magnetic field is?

If a particle of charge 10^-12C moving with velocity of 10^5 m/s experience a force of 10^-10 N in y direction due to magnetic field,then the minimum value of magnetic field is?

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If a particle of charge 10^-12C moving with velocity of 10^5 m/s experience a force of 10^-10 N in y direction due to magnetic field,then the minimum value of magnetic field is?

If a particle of charge 10^-12C moving with velocity of 10^5 m/s experience a force of 10^-10 N in y direction due to magnetic field,then the minimum value of magnetic field is?

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