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If a particle of charge 10^-12C moving with velocity of 10^5 m/s experience a force of 10^-10 N in y direction due to magnetic field,then the minimum value of magnetic field is? If a particle of charge 10^-12C moving with velocity of 10^5 m/s experience a force of 10^-10 N in y direction due to magnetic field,then the minimum value of magnetic field is?
Dear RajitBy Lorentz ForceF = q * v* B sin@NowB = F/q*v* sin@For minimum magnetic field sin@ is maximum = 1HenceB = 10-10/105 *10-12 B = 10-3 T in Z direction RegardsArun (askIITians forum expert)
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