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how to prove and derive F=qvBsin(x)........this formula is given directly in books

how to prove and derive F=qvBsin(x)........this formula is given directly in books

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3 Answers

Rinkoo Gupta
askIITians Faculty 80 Points
8 years ago
B is the magnetic flux density

I ( current ) = rate of flow of charges = q / time

so , F = B L ( q / t ) sin theta

L / t = V ( velocity )

so , F = B q V sin theta

that's it :)
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
Devkanti
19 Points
5 years ago
F proportional qF proportional BF proportional Vsin theta=> F proportional BqVsin thetaF= KBqVsin thetaAt SI, K=1=> F= BqV sin theta=> F(vector)= q{V(vector)×B(vector)}
T.Naveen Kumar Reddy
13 Points
4 years ago
That will be correct but by giving information not be sufficient bilsin theta ni bqv sin theta marchadam matter how to prove linkage of all

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