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        how to prove and derive F=qvBsin(x)........this formula is given directly in books
4 years ago

Answers : (3)

Rinkoo Gupta
askIITians Faculty
80 Points
							B is the magnetic flux density

I ( current ) = rate of flow of charges = q / time

so , F = B L ( q / t ) sin theta

L / t = V ( velocity )

so , F = B q V sin theta

that's it :)
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
4 years ago
Devkanti
19 Points
							F proportional qF proportional BF proportional Vsin theta=> F proportional BqVsin thetaF= KBqVsin thetaAt SI, K=1=> F= BqV sin theta=> F(vector)= q{V(vector)×B(vector)}
						
one year ago
T.Naveen Kumar Reddy
13 Points
							That will be correct but by giving information not be sufficient bilsin theta ni bqv sin theta marchadam matter how to prove linkage of all
						
8 months ago
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