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Magnetism

how to prove and derive F=qvBsin(x)........this formula is given directly in books

Priya Bahuguna

12 Years agoGrade

3 Answers

Rinkoo Gupta

12 Years ago

B is the magnetic flux density

I ( current ) = rate of flow of charges = q / time

so , F = B L ( q / t ) sin theta

L / t = V ( velocity )

so , F = B q V sin theta

that's it :)

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

Devkanti

9 Years ago

F proportional qF proportional BF proportional Vsin theta=> F proportional BqVsin thetaF= KBqVsin thetaAt SI, K=1=> F= BqV sin theta=> F(vector)= q{V(vector)×B(vector)}

T.Naveen Kumar Reddy

8 Years ago

That will be correct but by giving information not be sufficient bilsin theta ni bqv sin theta marchadam matter how to prove linkage of all

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