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For a wire as shown. Carrying a current 10A. The magnetic field at 0 is....

Sridhar , 6 Years ago
Grade 12
anser 1 Answers
Eshan

Last Activity: 6 Years ago

Dear student,


The magnetic field due to each semi-infinitely long current carrying wire is out of the plane and equal to

\dfrac{\mu_0I}{4\pi R}=10\times ^{-7}\times \dfrac{10}{0.005}T=2\times 10^{-4}T

The magnetic field from the turning edges can be neglected since it is very far from the point. Also the segments of wire along line passing through the point will be zero.

Hence net magnetic field at point O=2\times (2\times 10^{-7}T)=4\times 10^{-7}T

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