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drive the expression for the magetic iduction a point on the axis of a current carrying circular coil using boit savart law
From Bio-Savart’s Law,dB = u*i*(dl x r)/4pi*r^2where u = 4pi x 10^-7From the construction magnetic field at a distance x from the circular coil to a point P,dB = uidlsinthetha/4pi*(x^2 + r^2)On Integrating we get,B = unIr^2/2(x^2 + r^2)^(3/2)
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