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drive the expression for the magetic iduction a point on the axis of a current carrying circular coil using boit savart law

peethani dileep kumar , 8 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

From Bio-Savart’s Law,
dB = u*i*(dl x r)/4pi*r^2
where u = 4pi x 10^-7
From the construction magnetic field at a distance x from the circular coil to a point P,
dB  = uidlsinthetha/4pi*(x^2 + r^2)
On Integrating we get,
B = unIr^2/2(x^2 + r^2)^(3/2)
 

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