drive the expression for the magetic iduction a point on the axis of a current carrying circular coil using boit savart law

Question

Vikas TU · Answer

From Bio-Savart’s Law, dB = u*i*(dl x r)/4pi*r^2 where u = 4pi x 10^-7 From the construction magnetic field at a distance x from the circular coil to a point P, dB = uidlsinthetha/4pi*(x^2 + r^2) On Integrating we get, B = unIr^2/2(x^2 + r^2)^(3/2)

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drive the expression for the magetic iduction a point on the axis of a current carrying circular coil using boit savart law

drive the expression for the magetic iduction a point on the axis of a current carrying circular coil using boit savart law

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