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calculate the magnetic filed at the center of a square current loop of side a

calculate the magnetic filed at the center of a square current loop of side a
 

Grade:12th pass

1 Answers

Syed suha
49 Points
4 years ago
We know the sides of square are at right angles, draw a perpendicular bisector through 2 adjacent corners and you will get 45°angle. Draw another perpendicular bisector of that side enclosed in the triangle you have got and calculate it's length (tan theta= prerpendicular/ a/2) you will get it a/2 …
Magnetic field due to one side of square will be μ•i(cos45°-cos45°)/4πa
B=μ•i/√2πa (inside the plane of paper)
Directions and magnitude of magnetic field of all sides is same so you just need to add up the magnetic field...
Btotal=4× μ•i/√2πa
Btotal = 2√2μ•iπa....
Hope it clears!!!!
Thank you!!!

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