At t=0 the switch s of the adjacent network is closed. The connector has mass m, length l and resitanceR; it is free to move on the rails. The capacitance of the capacitor is C. It is initially uncharged and a uniform magnetic field exists into the plane of the paper. What is the charge on the capacitor after a long time??...........answer is EmC/( C2B2l2 + m)..........please post the solution specially the portion wher velocity of the connector is substituted.
Radhika Batra , 10 Years ago
Grade 11
1 Answers
ROSHAN MUJEEB
Last Activity: 4 Years ago
Solution : qC+Bvl=εqC+Bvl=ε q=C(ε−Bvl)q=C(ε-Bvl) Now,mdvdt=Bilmdvdt=Bil mdv=Blidtmdv=Blidt m∫v0dv=Bl∫q0dqm∫v0dv=Bl∫q0dq mv=Blqmv=Blq ∴q=mvBl∴q=mvBl...(i) From (i) and (ii) mvBl=Cε−CBlvmvBl=Cε-CBlv ⇒v=CBlε(m+CB2l2)
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